f[n]=[n-1][n-2]

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Solution for f[n]=[n-1][n-2] equation:


Simplifying
f[n] = [n + -1][n + -2]

Multiply f * n
fn = [n + -1][n + -2]

Reorder the terms:
fn = [-1 + n][n + -2]

Reorder the terms:
fn = [-1 + n][-2 + n]

Multiply [-1 + n] * [-2 + n]
fn = [-1[-2 + n] + n[-2 + n]]
fn = [[-2 * -1 + n * -1] + n[-2 + n]]
fn = [[2 + -1n] + n[-2 + n]]
fn = [2 + -1n + [-2 * n + n * n]]
fn = [2 + -1n + [-2n + n2]]

Combine like terms: -1n + -2n = -3n
fn = [2 + -3n + n2]

Solving
fn = 2 + -3n + n2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'n'.
f = 2n-1 + -3 + n

Simplifying
f = 2n-1 + -3 + n

Reorder the terms:
f = -3 + 2n-1 + n

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